2c^2+20c-1=-1c-8

Solution for 2c^2+20c-1=-1c-8 equation:

2c^2+20c-1=-1c-8

We move all terms to the left:

2c^2+20c-1-(-1c-8)=0

We get rid of parentheses

2c^2+20c+1c+8-1=0

We add all the numbers together, and all the variables

2c^2+21c+7=0

a = 2; b = 21; c = +7;
Δ = b2-4ac
Δ = 212-4·2·7
Δ = 385
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(21)-\sqrt{385}}{2*2}=\frac{-21-\sqrt{385}}{4}
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(21)+\sqrt{385}}{2*2}=\frac{-21+\sqrt{385}}{4}
$